#1
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Normal Distribution Table result wanted
Hello everyone,
In "Gambling Theory and Other Topics" Mason gives a formula you can use to work out how many sessions you will lose. Solving for "X" with my own results I arrived at a figure of -0.11 In Mason's example, X = -0.13 He then wrote: "From a normal distribution table, we see that -0.13 standard deviations corresponds to the 44.83 percentage point. This means that with the parameters given you should expect to be a loser in about 45% of your five hour playing sessions." Could one of you with access to a suitable normal distribution table tell me what percentage -0.11 corresponds to? I've tried finding one on the internet, but have been baffled by the amount and different types of table available. Thanks, - roGER |
#2
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Re: Normal Distribution Table result wanted
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#3
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Re: Normal Distribution Table result wanted
Thanks very much!
That's perfect. - roGER |
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