#1
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three starting days == three chances to start?
with three starting days, i wonder if there'll be any instances of someone busting out on day 1A or 1B and then trying to buy in as an alternate for the remaining day(s).
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#2
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Re: three starting days == three chances to start?
[ QUOTE ]
with three starting days, i wonder if there'll be any instances of someone busting out on day 1A or 1B and then trying to buy in as an alternate for the remaining day(s). [/ QUOTE ] Someone will at least try. |
#3
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Re: three starting days == three chances to start?
[ QUOTE ]
[ QUOTE ] with three starting days, i wonder if there'll be any instances of someone busting out on day 1A or 1B and then trying to buy in as an alternate for the remaining day(s). [/ QUOTE ] Someone will at least try. [/ QUOTE ] only to find out 7.5 million dollars later that they're gona be disqualified for entering twice. |
#4
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Re: three starting days == three chances to start?
[ QUOTE ]
only to find out 7.5 million dollars later that they're gona be disqualified for entering twice. [/ QUOTE ] OK, so, compromise: they should be allowed to re-enter as an alternate on one of the other "first days", but the re-entry fee is 7.5 million dollars. God damn, I am MINUTES ahead of my time. |
#5
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Re: three starting days == three chances to start?
Since you need a WSOP players card to buy in, wouldn't that make it a bit harder to re-enter the main event?
Kevin... |
#6
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Re: three starting days == three chances to start?
You need to buy in before the start of the first day. There is no way to buy in on the 8th or 9th.
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#7
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Re: three starting days == three chances to start?
you have to register before the tourney starts so it is impossible to do this.
indy |
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