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#1
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Im looking to determine the probability that given a deck of X cards, Y of them the same (by rank[4] or suit[13]) what is the probability that at least one has been chosen after Z cards are dealt. To make it concrete lets use the discreet example of -- 'What is the probability that at least 1 heart has been chosen after 10 cards are dealt from a standard deck?'
Step 1) 1 - Probability of No hearts Dealt After 10 Cards Step 2) Probability of No hearts Dealt After 10 Cards = Ways to choose 10 cards without a heart / Total Ways to Choose 10 cards Step 3) 1 - [c(42, 10) / c(52,10)] Is this correct? and would the general formula be 1 - [c(X-Y,Z)/c(X,Z)]? |
#2
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[ QUOTE ]
Step 1) 1 - Probability of No hearts Dealt After 10 Cards [/ QUOTE ] Correct [ QUOTE ] Probability of No hearts Dealt After 10 Cards = Ways to choose 10 cards without a heart / Total Ways to Choose 10 cards [/ QUOTE ] Correct [ QUOTE ] 1 - [c(42, 10) / c(52,10)] [/ QUOTE ] Incorrect. It needs to be 1-[c(39,10)/c(52,10)] You have to choose the ten cards from the 39 that are not hearts. Cobra |
#3
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LoL! Thank you... Just like me to get the 'higher' level math correct and butcher the arthimetic.
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