#1
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odds of two people getting dealt AA?
This situation came up in a game i was playing yesterday, and i was just wondering if anybody knew the odds of that happening?
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#2
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Re: odds of two people getting dealt AA?
(10 choose 2)*(6/(52 choose 2))*(1/(50 choose 2))
About 1 in 6016 |
#3
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Re: odds of two people getting dealt AA?
thanks alot
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#4
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Re: odds of two people getting dealt AA?
It's one of those rare things that really does happen every so often.
I hadn't ever seen it until this past week - when it happened in two consecutive sessions of B&M play! The second time I was involved - and still made a nice tidy profit on the hand. The final pot was split, of course, but we had a 5-way capped preflop, thanks to some limpers who got taken for a nasty ride by me raising from the small blind and the other guy limp-reraising from sixth or seventh seat. |
#5
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Re: odds of two people getting dealt AA?
Hey gaming mouse, here's one for ya:
I saw AA vs. AA today in a single table qualifier to the million guaranteed this weekend (which I won [img]/images/graemlins/grin.gif[/img]) Anyways, what are the odds of AA vs. AA being dealt, and one of the A's making a four flush to take the pot? Sucked for one guy. |
#6
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Re: odds of two people getting dealt AA?
[ QUOTE ]
Hey gaming mouse, here's one for ya: I saw AA vs. AA today in a single table qualifier to the million guaranteed this weekend (which I won [img]/images/graemlins/grin.gif[/img]) Anyways, what are the odds of AA vs. AA being dealt, and one of the A's making a four flush to take the pot? Sucked for one guy. [/ QUOTE ] That's awesome. I hope you rubbed that all over his face. Anyway, let's do 4 or 5 flush, since either has the same effect. 4*((12 choose 4)*36 + (12 choose 5))/(48 choose 5) = 0.0434782609 Now multiply that by the original answer: About 1 in 138368. Nice work. |
#7
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Re: odds of two people getting dealt AA?
So gamingmouse...you are my mathmatical god...wow...just wow
i got a long way to go [img]/images/graemlins/confused.gif[/img] |
#8
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Re: odds of two people getting dealt AA?
If you are dealt AA, the odds of someone else being dealt AA are n/C(50,2) = n/1225, where n is the number of your opponents.
The odds of two people being dealt AA (from outside view, i.e. not taking into account any hole cards) are C(n,2)*C(4,2)/(C(50,2)*C(48,2)) |
#9
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Re: odds of two people getting dealt AA?
Sorry, the last formula is C(n,2)*C(4,2)/(C(52,2)*C(50,2))
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