#1
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Gambler\'s Ruin
How many buyins do you need to have to make going all in preflop every time a +EV play?
Maybe this should be posted in the stats forum... |
#2
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Re: Gambler\'s Ruin
????
How could this ever be a +EV play? |
#3
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Re: Gambler\'s Ruin
there is no number. going all-in preflop every time is -EV. summing an infinite number of -EV situations doesn't make a winning one.
fim |
#4
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Re: Gambler\'s Ruin
Just look at it this way.
If your going all in every hand, your favored against 50% of the hands over the long run. Everyone else is getting to look at their cards before calling your ridiculous raise. Soooooo they win. |
#5
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Re: Gambler\'s Ruin
4.5, but only if you aren't being raked. If you are, then it's 4.68.
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#6
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Re: Gambler\'s Ruin
shhhhhhhh, don't tell him the secret....
fim |
#7
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Re: Gambler\'s Ruin
Damn..another 2+2 novice learned the "secret"
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#8
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Re: Gambler\'s Ruin
Wait, the secret is "If you are going to post moronic probability questions with no answer, you should do it in the probability forum?" Cool.
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#9
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Re: Gambler\'s Ruin
The answer is 0.
Proof: With zero buyins, there are no possible plays, so there are no +EV plays, therefore there are no +EV plays that are not all-in, therefore every all-in play is +EV. |
#10
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Re: Gambler\'s Ruin
mmmmm...that's spiffy.
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