#1
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David Sklansky Wrong?
Can someone explain this excerpt for me:
" For instance, suppose you're an 8-1 underdog and the pot of- fers 7-1. (I disregard future-round bets for the purpose of this discussion.) Say someone bet $10 into a $60 pot. You would now fold and save $10. But you really didn't save the full $10. The intuitive player might call in this spot and cost himself $10 seven out of eight times. However, he gains $70 the one out of eight times that he makes his hand. His bad play only costs an average of $1.25, which isn't much. " I'm certainly not a math wiz but isn't the intuitive player missing his draw 8 times for a loss of -80 and hitting his hand once for +70? Hence he's losing 10 dollars for 9 plays, bringing the loss to 1.11 per play. footnote: the excerpt is from Getting The Best of It posted on this site. |
#2
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Re: David Sklansky Wrong?
10/8 = 1.25.
ok I see where your mistake is. He makes his hand once, and misses 7 times. Melch |
#3
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Re: David Sklansky Wrong?
[ QUOTE ]
10/8 = 1.25. ok I see where your mistake is. He makes his hand once, and misses 7 times. Melch [/ QUOTE ] He's an 8-1 underdog, so out of 9 hands he makes his hand once and loses 8 times, costing him 10/9 = $1.11 per hand. You and Sklansky are both wrong, and KeyToTheMint is right. |
#4
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Re: David Sklansky Wrong?
Yeah, he switched between 8-1 and 7-1 underdog sometime in the example, and I guess his math included parts from both.
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