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#11
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Suppose a player has 2 [img]/images/graemlins/spade.gif[/img] 2 [img]/images/graemlins/heart.gif[/img]. For this player
to have absolutely zero equity, he cannot play the board with all the other players doing likewise. Thus, the board cannot be allowed to have any straight flush possibilities. Clearly, some other player must have 2 [img]/images/graemlins/diamond.gif[/img] 2 [img]/images/graemlins/club.gif[/img] If the other hands are as below, no straights are possible and therefore no straight flushes. 7 [img]/images/graemlins/spade.gif[/img] 7 [img]/images/graemlins/heart.gif[/img] 7 [img]/images/graemlins/diamond.gif[/img] 7 [img]/images/graemlins/club.gif[/img] Q [img]/images/graemlins/spade.gif[/img] Q [img]/images/graemlins/heart.gif[/img] Q [img]/images/graemlins/diamond.gif[/img] Q [img]/images/graemlins/club.gif[/img] Thus, with a total of five other hands, it is possible for 22 to be drawing dead. Here's an easy question to answer! What hands in holdem require the least number of other hands competing to have exactly zero equity? You should be able to immediately determine which hands they are and what the least number of hands will be. |
#12
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Actually, should have 55, 55, TT, TT as other hands.
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#13
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Sh!t.
I mean, add the other AA's -- that should do it. 'hoof |
#14
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ad ah
as kc ac ks tc 7s 7c ts 7d 7h td th 2s 3d 2h 3c kh kd http://twodimes.net/h/?z=219517 pokenum -h ad ah - as kc - ac ks - tc 7s - 7c ts - 7d 7h - td th - 2s 3d - 2h 3c - kh kd Holdem Hi: 201376 enumerated boards cards win %win lose %lose tie %tie EV Ad Ah 135708 67.39 64288 31.92 1380 0.69 0.676 As Kc 1626 0.81 198370 98.51 1380 0.69 0.010 Ks Ac 1626 0.81 198370 98.51 1380 0.69 0.010 7s Tc 110 0.05 164974 81.92 36292 18.02 0.081 Ts 7c 83 0.04 165001 81.94 36292 18.02 0.081 7d 7h 137 0.07 194563 96.62 6676 3.32 0.012 Td Th 56 0.03 195992 97.33 5328 2.65 0.009 2s 3d 27 0.01 177045 87.92 24304 12.07 0.060 3c 2h 27 0.01 177045 87.92 24304 12.07 0.060 Kd Kh 0 0.00 201376 100.00 0 0.00 0.000 |
#15
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You made the same mistake, all aces need to be out or else A4444 is a chop, for example.
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#16
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2222 is dead to 3333!
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#17
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If the last hand is AA, there won't be nine other hands
that give AA an equity of zero. If the last hand is a smaller pocket pair, say Ks Kh, you can take out the other KK, the two pocket aces, two pocket tens and two pocket fives so now the KK has zero equity. If the pair is say 5s 5h, take out the other fives, the two pocket aces, two pocket sixes and two pocket tens. Now if the tenth hand is A [img]/images/graemlins/spade.gif[/img] K [img]/images/graemlins/spade.gif[/img], pick these hands: A [img]/images/graemlins/heart.gif[/img] A [img]/images/graemlins/diamond.gif[/img] K [img]/images/graemlins/heart.gif[/img] K [img]/images/graemlins/diamond.gif[/img] A [img]/images/graemlins/club.gif[/img] K [img]/images/graemlins/club.gif[/img] Q [img]/images/graemlins/spade.gif[/img] J [img]/images/graemlins/spade.gif[/img] T [img]/images/graemlins/spade.gif[/img] 9 [img]/images/graemlins/spade.gif[/img] 8 [img]/images/graemlins/spade.gif[/img] 7 [img]/images/graemlins/spade.gif[/img] 6 [img]/images/graemlins/spade.gif[/img] 5 [img]/images/graemlins/spade.gif[/img] T [img]/images/graemlins/heart.gif[/img] T [img]/images/graemlins/diamond.gif[/img] 5 [img]/images/graemlins/heart.gif[/img] 5 [img]/images/graemlins/diamond.gif[/img] T [img]/images/graemlins/club.gif[/img] 5 [img]/images/graemlins/club.gif[/img] Now, if a spade flush is possible, the 6s 5s makes the nut straight flush. Similarly, for AY suited, there will be a possible straight flush that can be made and so nine hands can be chosen to give this hand zero equity. For a smaller suited hand, say K [img]/images/graemlins/spade.gif[/img] Q [img]/images/graemlins/spade.gif[/img], just pick the following: A [img]/images/graemlins/spade.gif[/img] T [img]/images/graemlins/spade.gif[/img] K [img]/images/graemlins/heart.gif[/img] K [img]/images/graemlins/diamond.gif[/img] Q [img]/images/graemlins/heart.gif[/img] Q [img]/images/graemlins/diamond.gif[/img] A [img]/images/graemlins/club.gif[/img] K [img]/images/graemlins/club.gif[/img] Q [img]/images/graemlins/club.gif[/img] T [img]/images/graemlins/club.gif[/img] A [img]/images/graemlins/heart.gif[/img] A [img]/images/graemlins/diamond.gif[/img] T [img]/images/graemlins/heart.gif[/img] T [img]/images/graemlins/diamond.gif[/img] 5 [img]/images/graemlins/spade.gif[/img] 5 [img]/images/graemlins/heart.gif[/img] 5 [img]/images/graemlins/diamond.gif[/img] 5 [img]/images/graemlins/club.gif[/img] For nonsuited hands, the task is simpler. |
#18
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You don't need the two 23 hands. A 6 high straight flush on board doesn't play because one of the 77's beats it.
'hoof |
#19
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Here are two threads showing how pocket aces could be drawing dead preflop:
November 2002 thread started by JTG51 March 2003 thread started by rharless |
#20
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Good work! Your example gives the minimum number of
opponents for AA to have zero equity. Here is the argument for at least eleven opponents: Say our hero has A [img]/images/graemlins/spade.gif[/img] A [img]/images/graemlins/heart.gif[/img]. The other hands must have at least 8 spades and 8 hearts because of the flush possibilities: with only four consecutive spades and four consecutive hearts outstanding, as long as the top card of the sequences isn't the rank of a king, then it allows all four of the cards of the suit to show up and gives one of the other hands a straight flush. Also, with four missing in a suit with a gap, as long as the top card is not a king, if these four appear on board, one of the hands makes a straight flush. The A [img]/images/graemlins/diamond.gif[/img] and A [img]/images/graemlins/club.gif[/img] must also be in the other hands so that our hero can't make trips and win and to avoid a straight flush in diamonds or clubs on board that everyone plays, another two diamonds and two clubs must be in the other hands to make it impossible for a straight flush to play on board. Altogether, that is a minimum of 22 cards or eleven hands. |
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