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  #11  
Old 06-19-2005, 04:13 AM
DcifrThs DcifrThs is offline
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Default COrrection...

[ QUOTE ]
Sorry, didn't see you weren't yet jumping into different combinations...

[/ QUOTE ]

no you were right. im pulling up excel to get it correct right now.

# is well over 100billion i think

its <93C1....93C5> * <12C3.....12C3> for each of the varying # of alcohols and mixers. im not writing it all out.

sorry for the earlier mistake
Barron
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  #12  
Old 06-19-2005, 04:17 AM
DougOzzzz DougOzzzz is offline
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Default Re: COrrection...

[ QUOTE ]
[ QUOTE ]
Sorry, didn't see you weren't yet jumping into different combinations...

[/ QUOTE ]

no you were right. im pulling up excel to get it correct right now.

# is 12,105,534,100

so you can make 12 billion different drinks.

its <93C1....93C5> (vector) * <12C3.....12C3> (vector)

sorry for the earlier mistake
Barron

[/ QUOTE ]

shouldn't it be <12C0....12C3> which is exactly what I did? why are you ignoring all the drinks with 0, 1, or 2 mixers?
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  #13  
Old 06-19-2005, 04:26 AM
DcifrThs DcifrThs is offline
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Default Re: COrrection...

yes. yours is right.

-Barron
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  #14  
Old 06-20-2005, 03:02 AM
Ulysses Ulysses is offline
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Default Re: A dumb bar bet...

You guys are all ignoring different volumes of the same mixers and alcohols used to create different drinks. So, it's a lot more.
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  #15  
Old 06-21-2005, 02:38 PM
parttimepro parttimepro is offline
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Default Re: A dumb bar bet...

Yes, it's very nearly infinite. Hell, you don't need all those different kinds of alcohol to make an infinite number of drinks. Just take gin and vermouth. You can serve 100% gin or 100% vermouth. You can make a martini with 50/50. A dry martini with 75% gin. A slightly less dry martini with 62.5% gin... you see where I'm going with this.

Eventually you get to the point where different drinks vary only by 1 molecule of gin and vermouth. This is functionally infinitely (i.e. the number of combinations is greater than the number of atoms in the universe), but let's try to estimate within a few orders of magnitude the actual number.

We'll say a drink is 200 mL and weighs about 200 g. 200 grams is about 11 moles of water, or 6.7 x 10^24 molecules. If there are only two types of liquor going into a drink, there are 6.7 x 10^24 drink combinations. With three types of liquor, it's ((6.7 x 10^24)^2)/2 = 2.2 x 10^49.

Perhaps some actuary can correct my statistics, but I believe with 9 liquors and 3 mixers, the number is very large.

Then you can add different drink sizes, etc. Whoever guessed the highest wins the bet.
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  #16  
Old 06-21-2005, 04:15 PM
drudman drudman is offline
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Default Re: A dumb bar bet...

Vee have over 10^49 types of beer, vrom all over zee vorld. Call me vhen you are ready.
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  #17  
Old 06-21-2005, 05:12 PM
Ulysses Ulysses is offline
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Default Re: A dumb bar bet...

[ QUOTE ]
You can make a martini with 50/50. A dry martini with 75% gin.

[/ QUOTE ]

You are really bad at making martinis.
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  #18  
Old 06-22-2005, 03:32 PM
parttimepro parttimepro is offline
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Default Re: A dumb bar bet...

[ QUOTE ]
You are really bad at making martinis.

[/ QUOTE ]
You're not fk'n kidding. Can't stand em, even if they are made right.

I do like those florescent girl drinks they call martinis and serve in martini glasses, but then, I also like Boone's Strawberry wine coolers. It really impresses the ladies to see me drinking that straight from the bottle.
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  #19  
Old 06-22-2005, 07:06 PM
SossMan SossMan is offline
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Default Re: A dumb bar bet...

[ QUOTE ]
You guys are all ignoring different volumes of the same mixers and alcohols used to create different drinks. So, it's a lot more.

[/ QUOTE ]

i'm quite sure that wasn't what the OP was getting at.
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  #20  
Old 06-22-2005, 08:38 PM
AlphaWice AlphaWice is offline
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Default Re: A dumb bar bet...

This is easy.

First, consider all the alcohol that goes into the drink. There are 93 + 93C2 + 93C3 + 93C4 + 93C5 combinations.

Second, consider all the nonalcohol that goes into the drink. There are 12 + 12C2 + 12C3 combinations.

So multiply those two together.
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