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  #1  
Old 08-17-2004, 12:35 PM
scarr scarr is offline
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Default Determining finish position when two out on same hand

From what I have seen in the tournaments online, the finish position when two people go
out at the same time is based on who had the most chips going into that hand.
The person with the most chips gets the higher finish position.

I played in a B&M tournament this weekend, and they said the finish position was determined
by who had the better final hand.

What is the reasoning for using the better hand, as opposed to the initial chip count, to determine
the finish position? As a player, I prefer the chip count.

-scarr
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  #2  
Old 08-17-2004, 01:17 PM
trillig trillig is offline
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Default Re: Determining finish position when two out on same hand

Which B&M is saying that, please?

Ridiculous...

-Bri
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  #3  
Old 08-17-2004, 01:30 PM
SossMan SossMan is offline
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Default Re: Determining finish position when two out on same hand

go to www.homepokertourney.com they have TDA rules. You can print them out and take them to the TD. Probably won't change anything, but it really should be standardized.
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  #4  
Old 08-17-2004, 01:39 PM
TomCollins TomCollins is offline
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Default Re: Determining finish position when two out on same hand

The answer is simple. Laziness. There is no easy way to know who started the hand with the most chips in B&M, especially if it was from two different tables. So they use this arbitrary measure. The better solution is to give it a "tie", like WSOP does.
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  #5  
Old 08-17-2004, 01:59 PM
scarr scarr is offline
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Default Re: Determining finish position when two out on same hand

[ QUOTE ]
Which B&M is saying that, please?

[/ QUOTE ]

These are private tourneys in Texas.
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  #6  
Old 08-17-2004, 03:10 PM
trillig trillig is offline
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Default Re: Determining finish position when two out on same hand

Playing by their own rules, they don't exactly qualify as std public access Brick & Mortars, I'd be stunned to hear that rule in a regular B&M's tournament.

I could have 100 in chips left, another guy with 5000, and both knocked out by a guy with 10000 and wind up paid 1 place higher? YIKES! That is really bad!

YMMV,

-Bri
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  #7  
Old 08-17-2004, 05:03 PM
Easy E Easy E is offline
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Default Re: Determining finish position when two out on same hand

"I played in a B&M tournament this weekend, and they said the finish position was determined by who had the better final hand."

That's just stupid. If the two players had only been up against one another and all in, would the smaller stack get to stay in?
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  #8  
Old 08-17-2004, 05:04 PM
Easy E Easy E is offline
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Default Re: Determining finish position when two out on same hand

Unless there are no sidepots... no, even then, the size of the pot on each table could determine that.

It's beyond laziness
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  #9  
Old 08-18-2004, 12:52 AM
TomCollins TomCollins is offline
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Default Re: Determining finish position when two out on same hand

Not very easily with dead money. Again, I have seen it in two places where it is a tie if they finish on the same hand, even if one guy had a million chips, and another guy had 1 chip. WSOP did this for the main event, but instead of splitting the 10k, Harrah's paid them, both the prize money.
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