100/200 blind war

[DcifrThs]

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situation 1: he has a 6 and you bet/call.

situation 2: he has an 8 and calls your bet.

situation 3: you check he bets the 8 and you win.

situation 4: you check and he bets the 6 and you lose.

so...

E[1+2]= -(2)*.5 + .5*1=-.5

E[3+4]= .5*1 - .5*1=0


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nice post first of all, is E[1 + 2] the average equity of decisions 1 and 2?

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each set of possibilities is composed of an 8 and a 6. each 1 is 50% so im combining them for simplicity

Barron