Equity/Counting Outs in LO8.

[benwood]

RE:The problem posed in my last 2 posts.
If:C=no.of bets called=1.X=no.of bets returned=?.H1=no.of clean outs=1.H2=no.of tainted outs=2.B1=no.of bets rec'd if you win high=5.B2=no.of bets rec'd if you win low=2.P1=estimate of%of time that tainted cards are good=.75.P2=estimate of%of time low outs will scoop=.20.L=no.of low cards out=6.U=no.of unknown cards=44.
Then:
X=(H1)(B1)+[(P1)(H2)](B1)+[(P2)(L)](B1)+[(1-P2)(L)](B2)overU
X=(2)(5)+[(.75)(2)](5)+[(.2)(6)](5)+[(.8)(6)](2)over 44
X=10+6.5+6+9.6/44=32.1/44=.727=.73
Therefore,if your estimates are correct,for the 1 bet that you call,you will only get back.73 of a bet.Fold this puppy.
This has been fun.But it would be a complete miracle if these calculations were correct.If any of you good math guys would like to check this out,I would appreciate it.