Calculating the Odds.

[CJHunt]

Is it even possible to have 22 outs?

KQclubs

10J2 2 clubs

could be 21 outs... I can't think of how you could get to 22 though.

[ QUOTE ]
Is it even possible to have 22 outs?

KQclubs

10J2 2 clubs

could be 21 outs... I can't think of how you could get to 22 though.

[/ QUOTE ]

I can only come up with 21 outs on the flop, using your example.

You hold KJ clubs and your opponent holds 5h 5d. The flop comes Tc Jc 6h with two clubs. You can now hit 4 aces, 4 nines, 3 kings, 3 queens, and 7 clubs for 21 outs total.

The most outs I can think of on the turn would be 25 and that comes from a situation where we take the same hand and board above and then drop a six on the turn.

So now the setup is:

You: Kc Qc
Opponent: 5h 5d
Board: Tc Jc 6h 6d

You can now hit four aces (4) or (4) nines for your straight. You have 8 outs at this point.

You can also hit three remaining tens (3) or jacks (3) for two overpair with top kicker. This gives you an additional six outs for 14 total.

You then can also hit (3) remaining kings or queens (3) for top two pair, top kicker. This gives you another six outs, for 20 total.

You can then hit any club that is a 2, 3, 4, 7, or 8 giving you 5 remaining outs for 25 total. You can only hit 5 as the Tc/Jc/Kc/Qc is gone, then we already have two clubs alloted to your nines and aces for outs, and either a 6c or 5c would give your opponent the winning full house.

My numbers might be off slightly, correct me if so.