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Re: Cute Applicable Math Question
Ok. Here goes...
For a quick solution it is important to recognize 2 facts: 1. There must be a winner. 2. The winner must win twice in a row. P(I win twice in a row) = .6^2 = .36 P(I lose twice in a row) = .4^2 = .16 --> P(there is a winner for a given pair of coin flips) = .36 + .16 = .52 Since there must be a winner, we know that we can ignore the area of the probability space where there is no winner. Using bayes theorem: --> P(I win) = .36/.52 = .692308 |
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