whats the bankroll formula for small NL games?

[rheaume]

i.e. how much do i need to play in a live game thats set up like this

NO LIMIT HOLD EM 2/5 blinds, $50-$100 buyin. can rebuy at any time back up to 100.

i know, retarded blind structure, but hey, its the weakest live game ive ever seen and i need a good figure on how much $$$$$$ i need behind me to play it and be able to withstand the obvious variance of playing with backwoods retards

thanks

[swolfe]

B = -(SD^2/(2*WR))ln(r)

[rheaume]

[ QUOTE ]
B = -(SD^2/(2*WR))ln(r)

[/ QUOTE ]

hope thats sarcasm, cuz i have no frickin idea how to read that.

perhaps someone can translate that to english for me. please?

[Niediam]

2,000 - 2,500

[rheaume]

[ QUOTE ]
2,000 - 2,500

[/ QUOTE ]

ty sir

[swolfe]

[ QUOTE ]
2,000 - 2,500

[/ QUOTE ]
with stacks that short, i think it'd be a lot higher to have a reasonably low risk of ruin. if i were playing in the game, i'd want $600 to $1K in my pocket for rebuys until i got deep. even doubling up twice will leave you with 80BB stacks..

EDIT: and if this were my regular game, i'd want a bankroll of at least $5K or so...

[elus2]

looks like bankroll = (variance/(2*winrate))*natural_log(r)
i don't know what the variable r stands for though. the problem with the equation would be the fact that it takes forever for winrate to converge. i'd go with 50 buy-ins if you're gonna play at that game full-time. i can't imagine that over time, your money is going in as more than a 55% favorite here since the shorter stacks force you play for a buy-in whenever you flop top pair or better or some strong draw.

[swolfe]

[ QUOTE ]
[ QUOTE ]
B = -(SD^2/(2*WR))ln(r)

[/ QUOTE ]

hope thats sarcasm, cuz i have no frickin idea how to read that.

perhaps someone can translate that to english for me. please?

[/ QUOTE ]

B = bankroll
SD = standard deviation
WR = win rate
r = risk of ruin

[DavidC]

Is the ln(r) part of this "the 'lon' run"? [img]/images/graemlins/smile.gif[/img]