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Re: A dumb bar bet...
This is easy.
First, consider all the alcohol that goes into the drink. There are 93 + 93C2 + 93C3 + 93C4 + 93C5 combinations. Second, consider all the nonalcohol that goes into the drink. There are 12 + 12C2 + 12C3 combinations. So multiply those two together. |
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