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Math/Trigonometry Question
I am trying to figure out the length of an arc of a circle. I do not know the radius of the circle. I know the length of the chord that has the endpoints of the arc as its endpoints, and I also know the distance from the cord to the apex of the arc.
Intuitively I bvelieve I have enough information to get the length of the arc, but I am just at a loss [img]/images/graemlins/confused.gif[/img]. Van anyone help? |
#2
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Re: Math/Trigonometry Question
I'm thinking multiply the length of the cord by pi and then divide by 2?
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#3
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Re: Math/Trigonometry Question
This is wrong.
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#4
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Re: Math/Trigonometry Question
[ QUOTE ]
This is wrong. [/ QUOTE ] its not wrong if the chord goes through the center [img]/images/graemlins/cool.gif[/img] |
#5
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Re: Math/Trigonometry Question
[ QUOTE ]
I'm thinking multiply the length of the cord by pi and then divide by 2? [/ QUOTE ] This can't be correct as it doesn't use information about the distance of the chord to the apex of the arc. That is obviously important information. |
#6
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Re: Math/Trigonometry Question
R= (((A/2)^2) + (B^2)) / 2B
(R = radius) (A = Chord Length) (B = Arc Height) Angle in Radians = 2 * Arcsin((Chord Length) / (2 * Arc Radius)) Arc Length = Arc Radius * Angle in Radians |
#7
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Re: Math/Trigonometry Question
Thanks!!!!!!! OOT Rules, and I have now achieved the feat of billing my time for posting on 2+2!
Evan, if we ever meet, the drinks are on me! |
#8
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Re: Math/Trigonometry Question
[ QUOTE ]
Evan, if we ever meet, the drinks are on me! [/ QUOTE ] [img]/images/graemlins/grin.gif[/img] |
#9
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Re: Math/Trigonometry Question
Yargh, friggin trig. Hated that class. Anyways, could you explain to me why you divided by 2B when solving for the radius?
Isn't it just pythagorean's? |
#10
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Re: Math/Trigonometry Question
If you read my post where I said that divding by 2B was an error, forget that. It is correct. I just suck at checking simple math (I also suck at mixing up radius and diameter [img]/images/graemlins/shocked.gif[/img]). The correct formula is the one in my first post.
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