Simple Birthday Problem

[skeetshooter]

No, the probability must be 1/2 or greater that 2 people share the same birthday(out of all the people in the group). Sorry if that wasn't clear, that was tough to word correctly.

[The Legend]

Take the probability that two people don't have the same birthday, i.e. 364/365. Then given that, prob. that three don't have, i.e. (364/365)*(363/365). continue until it equals less than .5. aka 364!/((364-x)!*365^x))<.5

try 22, and its becomes .49. So the answer is 22 people. Cheers.