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#1
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Home game, NL. I'm the givee of the terrible beat. I'm holding A3 os, opponent is holding KK, flop is A K 8 rb.
Opponent moves all in, twice the size of the pot, I call. What are my odds of beating the trips? I absolutely need 1 of 2 remaining aces, as well as an 8 or a 3. I was thinking (2/47)*(6/46)=.0055%? btw turn was an A, river was an 8 she was pissed [img]/images/graemlins/smirk.gif[/img] MOOKS |
#2
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You know 7 of the cards, and you need one to be an A, and the other to be an A, 8, or 3
(2/45)*(7/44) = .00707 She is 99.3% to win |
#3
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You are both making it sound much worse than it is.
![]() A, then 8 or 3: 2x6 ways 3, then A: 3x2 ways 8, then A: 3x2 ways or, of course, two running aces. That's a whopping 26/(45*44)= 1.31% shot. 13 of 990 possible endings, if you don't like counting everything twice according to the order it comes. |
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