#1
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Optimal Strategy vs All-in-every hand: how do I calculate?
Gentlemen,
in S&M's Tournament Poker for Advanced Players, they talk about how, if two players are heads-up with $10k, and the blinds are (I believe) $100 each, and one player moves all-in preflop on every hand, the absolute best the other player can achieve is a slightly better than 61% chance of winning, and that's assuming he knows exactly what hands offer a big enough edge to warrant moving in preflop. I am trying to contrive a general function where you would input what proportion of the chips you have, and what size the blinds are, to come up with a probability P, which means that calling the all-in with any hand that has better than P probability of beating a random hand is the optimal play. For instance, in this specific example, assuming that it's the first hand, P=0.61, meaning that a call with 66+, A8s/ATo+, KJs, KQs or KQo is warranted. So... how do I even go about calculating this. Mr. Sklansky, if you're reading this, how did you come up with the formulas you reached in your book? Be as technical as necessary, anything I don't understand right away, I will research. I'm just itching to know! Moose. |
#2
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Re: Optimal Strategy vs All-in-every hand: how do I calculate?
I don't have any answers for you, Moose, but if I can add a plea of my own, I'd very much like to know how to calculate other percentages - like when the blinds are one-tenth of your stack, or one-fifth.
Thanks! |
#3
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Re: Optimal Strategy vs All-in-every hand: how do I calculate?
[ QUOTE ]
Gentlemen, in S&M's Tournament Poker for Advanced Players, they talk about how, if two players are heads-up with $10k, and the blinds are (I believe) $100 each, and one player moves all-in preflop on every hand, the absolute best the other player can achieve is a slightly better than 61% chance of winning, and that's assuming he knows exactly what hands offer a big enough edge to warrant moving in preflop. I am trying to contrive a general function where you would input what proportion of the chips you have, and what size the blinds are, to come up with a probability P, which means that calling the all-in with any hand that has better than P probability of beating a random hand is the optimal play. For instance, in this specific example, assuming that it's the first hand, P=0.61, meaning that a call with 66+, A8s/ATo+, KJs, KQs or KQo is warranted. So... how do I even go about calculating this. Mr. Sklansky, if you're reading this, how did you come up with the formulas you reached in your book? Be as technical as necessary, anything I don't understand right away, I will research. I'm just itching to know! Moose. [/ QUOTE ] Do a search for Eastbay's posts. The clearest statements on this topic on these boards were, imo, made by him. |
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