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[ QUOTE ]
Hi Bruce Thanks for the detailed explenation, I think I have got that now. Just one more quick example to check that I fully understand it with more than 2 outcomes, suppose for example I was playing dice, where I was paid 8-1 when I hit a 6 and lost when I missed, my E.V. here would 0.5 and 5 times out of 6 I would be 1.5 times below average and the other 1 time I would be 7.5 above average, so I would work out my variance as follows : (5*(-1.5^2) + 7.5^2)/6 = 11.25 and my standard deviation would be 3.35, is that correct? Thanks again for your help Joe. [/ QUOTE ] That's correct. |
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