Whats fair?

[King_J]

20 handed trny. There are only two players left.
They both have around 10 000 chips each. Blinds are 2000-4000

Button is dealt A [img]/forums/images/icons/diamond.gif[/img] Q [img]/forums/images/icons/diamond.gif[/img] and moves all-in
Big blind calls with A [img]/forums/images/icons/club.gif[/img] K [img]/forums/images/icons/heart.gif[/img]

Whats the most fair result? My opionion in another post

[Dynasty]

AK will win this about 70% of the time.

So, if they're going to agree to a deal without seeing a flop, they should split the difference between the 1st and 2nd place prize money 70/30.

Example: 1st place $200, 2nd place $100.

Player with AK gets 100 + (100*.7) = $170
Player with AQ gets 100 + (100*.3) = $130

[Cyrus]

I may be wrong but I have the suspicion that King J is not looking for any kind of "fair deal" but is after the most righteous, the most morally correct result. [img]/forums/images/icons/cool.gif[/img]

Since he is not interested in the mathematically correct split or the players' strength, what else is there?

[King_J]

I know that AK is a big favorite against AQs. I also know that this question is strange.

But, I consider a split to be the most fair result afther the river.

[Dynasty]

Why is a 50/50 split fair?

[King_J]

There is no split for the cash. There might not even be money involved.
I just wanna have the most fair result for the hand. It is just a silly question. But I guess Dynasty thinks that AKo should win?

[Al_Capone_Junior]

I too think this is more of a moral and righteous question than a theoretical mathematical question.

I think the hand should be played out and no deals made. Dynasty might be right about the 70/30 thing, I haven't run any simulations on the matter. But even so, run the cards, pay your dues, and take your chances.

And don't tempt the gods, they are fickle.

al

[danderso8]

check your math...

Player with AK gets 100 + (100*.7) = $170 = 56.7% of total
Player with AQ gets 100 + (100*.3) = $130 = 43.3%

total pot is $300. The correct way to figure this split (or in general, a similar split, among n players) is

Money to player i =(1st place money + 2nd + ... + nth place money)* (percent of time player i is expected to win with his hand)

So, for this simple case, the split should be $210 and $90.

If you've been splitting your way, you've been either ripping off, or getting ripped off. [img]/forums/images/icons/wink.gif[/img]

[Dynasty]

check your math...

total pot is $300. The correct way to figure this split (or in general, a similar split, among n players) is

Money to player i =(1st place money + 2nd + ... + nth place money)* (percent of time player i is expected to win with his hand)

So, for this simple case, the split should be $210 and $90.


So, you think a $210/$90 split is fair despite the fact the 2nd place finisher is guaranteed a $100 prize?

If the 2nd place finisher is guaranteed $100, how can it be fair for him to accept less than that in a deal?

My initial calculations were correct. You must start from the premise that the 2nd place finisher is guaranteed $100, not $0. They are only making a 70/30 split of the $100 difference between 1st and 2nd place.

If you've been splitting your way, you've been either ripping off, or getting ripped off.

[Cyrus]

It seems that Dynasty is talking about tourney deals while danderso8 is talking about a deal on this particular pot, the AKvAQ situation.