#1
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Odds of flopping 2Pair or better holding two different ranks.
Hi
Anyone know the odds of flopping 2Pair or better holding two different ranks. Fx. XY. Flop: XXX,YYY,XXY,YYX,XXa,YYa,XYa. Another question: Say you are holding A8 in NL. Someone raise from EP. What are the odds flopping A8x,88x if he holds an Ace and a card that isnt an 8 ? |
#2
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Re: Odds of flopping 2Pair or better holding two different ranks.
Given starting hole cards X and Y where X > Y:
2 Pair using both hole cards: Flops of XYa = 3*3*44 = 396 (a not X or Y) Trips (using one hole card): Flops of XXa = ((3*2)/2)*44 = 132 Flops of YYa = ((3*2)/2)*44 = 132 Full House: Flops of XXY = ((3*2)/2)*3 = 9 (Nut) Flops of XYY = ((3*2)/2)*3 = 9 (Non-nut) Quads: Flops of XXX = 1 Flops of YYY = 1 Total # of possible flops = 19,600 Total # of flops 2 pair or better = 680 Probability = 680/19,600 = 3.47% Lost Wages |
#3
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Re: Odds of flopping 2Pair or better holding two different ranks.
Thx, bookmarked [img]/images/graemlins/smile.gif[/img]
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