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Post deleted by Mat Sklansky
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#2
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
From the twodimes.net poker hand analyzer:
1) Same suited: cards win %win lose %lose tie %tie EV As Ah 1410336 82.36 292660 17.09 9308 0.54 0.826 Ks Kh 292660 17.09 1410336 82.36 9308 0.54 0.174 Equity for KK: 297314/1712304 or about 0.173633887 2) One suit different: cards win %win lose %lose tie %tie EV As Ah 1399204 81.71 305177 17.82 7923 0.46 0.819 Ks Kd 305177 17.82 1399204 81.71 7923 0.46 0.181 Equity for KK: 309138.5/1712304 or about 0.180539495 3) Both suits different: cards win %win lose %lose tie %tie EV As Ah 1388072 81.06 317694 18.55 6538 0.38 0.813 Kc Kd 317694 18.55 1388072 81.06 6538 0.38 0.187 Equity for KK: 320963/1712304 or about 0.187445103 Since the combinations above have a ratio of 1:4:1, the average EV is approximately 0.180539495323. If you know the exact suits, then use one of the other numbers above. The equity for AA is just 1-(equity for KK). |
#3
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texa
I don't know about Texas, but in Oregon KK is a big underdog. [img]/images/graemlins/grin.gif[/img]
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#4
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
The other posters answered how big an underdog KK is, but I don't think thats what you were asking.
I think you are asking what are the odds of an opponet having AA when you have KK. If you are heads-up the odds are about 1 in 204. At a full table each person has about a 1 in 204 chance of having Aces so at a 10 man table you should run into Aces about once every 22 times you have KK. Note: My answers aren't exact and I'm too lazy and/or incompetent to do the real math. |
#5
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
For an individual opponent, the odds of him having AA when
you have KK is 6/C(50,2) or 6/1225 or 203.1667 to 1 against. If there are more opponents, it will be approximately the number of opponents multiplied by 6/1225. The exact answer is n x (6/1225) - C(n,2) x (1/230300) where n is the number of opponents. |
#6
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
is the "- C(n,2) x (1/230300)" term an inclusion-exclusion term to subtract out the times you double-counted when two people have KK?
thanks, -tpir |
#7
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
Correct! Since there is no possibility of more than two of
the opponents holding AA, there are no other terms. BTW, I believe you intended "AA" instead of "KK" in your post. The term comes from the probability that two players have AA: there are C(n,2) choices of players among n opponents, and the probability that specifically two opponents have AA is just 6/C(50,2) x 1/C(48,2) = 6/1225 x 1/1128 = 230300. |
#8
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
yeah, i meant AA. thank you for the response. you and bozeman are the probability masters!!
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#9
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
Have you forgotten other gurus that make their presence felt
on these forums? Clearly, BruceZ comes to mind and there are quite a few others that have put up some meaningful posts! |
#10
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Re: Im sure its been posted, but what are the odds of AA vs KK in Texas?
i thought it was something like 1 in 220, but then i read your disclaimer about not being exact.. so nevermind!
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