#1
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Confidence interval question
Supposes you have a possibly biased coin. You flip it n times, getting m heads. What interval can you say it's probability of heads is in with 95% confidence? With 67% confidence?
Craig |
#2
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Re: Confidence interval question
If we can assume that n is large, then it should be:
p±1.96*sqrt(m(n-m)/n^3) for 95% confidence and p±0.98*sqrt(m(n-m)/n^3) for 67% confidence |
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