Probability

What is the probability that an opponent have one or two clubs when the board has four clubs, and how do I calculate it?
In Hold'em

Martin Carlsson
Aalborg, Denmark

Hi Martin

I assume that there are 4 cards on the board, and you do not have a club. There are 46 unseen cards, and 9 clubs left. You now have to calculate the probability that he does NOT have a club. Of 46 cards 37 are not clubs.
(37/46)*(36/45) = 64%. So in 36% of they time he will have one or more clubs.

Jesper Jørgensen, Denmark

Ok,tnx

Can you recommend a book that explains standard probability?
I don't need anything fancy (jet), just an introduction.

It is ok, if it is danish.

Martin Carlsson
Aalborg, Denmark

[paulish]

Get Chance: A Guide to Gambling, Love, The Stock Market & Just About Everything Else
by Amir D. Aczel. High Stakes, 2005.

[img]/images/graemlins/smile.gif[/img]

I just finished reading it. Great book!
I can recommend it to anyone, who want an introduction to probability.

[DoomSlice]

Questions like this are best left to the realm of theory, since the way an opponent plays a hand should tip you off more as to whether he has a club (conditional probability!).