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#1
08-11-2005, 11:54 AM
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prbability
could someone tell me what the chances of someone having KK if i hav AA in a 10 handed game i would appreciate it if u could explain how u arrived at the answer
thanks mprom 
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#2
08-11-2005, 12:16 PM
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Re: prbability
4/50 *3/49 *9=0.044081633
There are 50 unkown cards, so some has to first be dealt one of the four kings; next they have to get one of the three remaining kings out of 49 unknown cards. Finally there are nine people so multiply by nine.
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#3
08-11-2005, 12:59 PM
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Re: prbability
To put it another way if you are dealt KK 1000 times at a 10-hand table its likely 956 of those times you won't be up against someone with pocket Aces.
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#4
08-11-2005, 01:12 PM
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Re: prbability
If you're looking for the probability that a specific opponent has K-K, then it's simply C(4,2)/C(50,2) = 0.48979591%.
If you're looking for the probability that at LEAST ONE opponent has K-K, then it's: 9 * 6/C(50,2) - C(9,2)/C(50,4) = ~4.39% You need the inclusion/exclusion principle to get this one exactly right. Search function folks...search function.
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