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  #1  
Old 01-09-2003, 04:16 PM
Rick Nebiolo Rick Nebiolo is offline
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Default The Semantics of Expectation

A two-week old thread on the holdem forum regarding a Roy Cooke hand has just resurfaced. The following question regarding expectation is obviously simple mathematically; however, we are having some problems with the semantics of expectation. All help is appreciated.

The pot is $100. Your lone opponent bets $40 on the river. He either has a big hand that won’t fold to a raise or a total bluff. You have a hand that can beat a total bluff (let’s say ace high). A personal omnipotent poker genie that is always right and never lies (but won’t do math for you) tells you that there is a 50% chance your opponent is bluffing.

If you call, what is your expectation?

If you fold, what is your expectation?

What is the difference in expectation between calling and folding?


Regards,

Rick
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  #2  
Old 01-09-2003, 05:12 PM
BruceZ BruceZ is offline
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Default Re: The Semantics of Expectation

The pot is $100. Your lone opponent bets $40 on the river. He either has a big hand that won’t fold to a raise or a total bluff. You have a hand that can beat a total bluff (let’s say ace high). A personal omnipotent poker genie that is always right and never lies (but won’t do math for you) tells you that there is a 50% chance your opponent is bluffing.

If you call, what is your expectation?


.5($140) + .5(-$40) = $50

If you fold, what is your expectation?

$0. The expectation of a fold is always 0. You are dead certain to win exactly nothing so 1($0) = $0.

What is the difference in expectation between calling and folding?

[b]$50.

To compute expectation, simply compute the sum of each dollar amount that can be won or lost multiplied by the probability of winning or losing that dollar amount for every possible outcome.
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  #3  
Old 01-09-2003, 06:30 PM
Rick Nebiolo Rick Nebiolo is offline
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Default Re: The Semantics of Expectation

Bruce,

I'm on my way out for the day but let me ask another question. I'll check in late tonight.

Let's say a player is faced with a choice of folding or calling and calling has a positive expectation of $50. The player folds (obviously a mistake). What terms would you use to quanttify the magnitude of his mistake?

Regards,

Rick
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  #4  
Old 01-09-2003, 07:29 PM
BruceZ BruceZ is offline
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Default Re: The Semantics of Expectation

Let's say a player is faced with a choice of folding or calling and calling has a positive expectation of $50. The player folds (obviously a mistake). What terms would you use to quanttify the magnitude of his mistake?

Folding is an error that costs $50 in ev compared to calling. That is because folding has an ev of $0 while calling has a positive ev of $50.
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  #5  
Old 01-10-2003, 09:26 AM
Jay Jay is offline
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Default Re: The Semantics of Expectation

Here may be a dumb question. The ev is $50 and now suppose you had to bet $60 (maybe $20 has to go as a toke or something - as the full $60 going into the pot would change the ev), I'm assuming the correct play is a fold (since betting $60 to win ev of $50 is a losing play???)?
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  #6  
Old 01-10-2003, 01:07 PM
Graham Graham is offline
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Default Re: The Semantics of Expectation

I think I was responsible for returning to haunt Rick with this one...

For your question, I think that in the common understanding of EV that, if a certain play has an EV of +$50, then that means that when you put your $60 into the pot, then you expect - on average - to return $110 to your stack. The EV is over and above the actual amount you put at risk.

G
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  #7  
Old 01-10-2003, 01:12 PM
Graham Graham is offline
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Default Re: The Semantics of Expectation

This is really a response for Rick, but you mentioned it, Bruce. The problem has cropped up 'cos rick is looking at it as a relative error, whereas EV is really an absolute quantity.
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  #8  
Old 01-10-2003, 01:19 PM
MrRothstein MrRothstein is offline
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Default Re: The Semantics of Expectation

I hope I don't come across as clueless, but...
Why wouldn't you calculate the expectation on a fold like this:

.5(-140) + .5(40) = -50

Thanks
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  #9  
Old 01-10-2003, 01:37 PM
Graham Graham is offline
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Default Re: The Semantics of Expectation

Because expectation is what you win or lose beyond your betting stake.

A fold is betting $0 to win/lose exactly $0. Always.
You don't need to do a calculation for the EV of a fold; folding always has EV of $0.

Your calculation is simply the inverse of the true calculation for the EV of calling. You're thinking the same way as Rick and it makes my head hurt trying to avoid the confusion... [img]/forums/images/icons/crazy.gif[/img]


G
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  #10  
Old 01-10-2003, 02:41 PM
MrRothstein MrRothstein is offline
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Default Re: The Semantics of Expectation

I think I get it now.
The problem for me was that $0 EV for a fold did not demonstrate how bad it was in this situation. I guess you would just look at what you are giving up by folding (which is $50).
Is that right?

Thanks
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