|
|
#1
04-14-2005, 10:50 PM
|
|||
|
|||
3 card poker problems....
Ok so how in 3 card poker would you calculate the probability of recieving 3 of a kind? I figured it would be (C(4,3)*13)/C(52,3). This gives me a really small number though and unsure if it is correct.
And I am really unsure of how to compute the probability of getting a straight. I was thinking (12*4^3-48)/C(52,3). Does this seem right or not? Thanks in advance. SGS 
|
|
#2
04-14-2005, 11:09 PM
|
|||
|
|||
|
Re: 3 card poker problems....
[ QUOTE ]
Ok so how in 3 card poker would you calculate the probability of recieving 3 of a kind? I figured it would be (C(4,3)*13)/C(52,3). This gives me a really small number though and unsure if it is correct. And I am really unsure of how to compute the probability of getting a straight. I was thinking (12*4^3-48)/C(52,3). Does this seem right or not? Thanks in advance. SGS [/ QUOTE ] 3 of kind looks right. Straight looks right except for the " - 48" part. Where are you getting that?
|
|
#4
04-15-2005, 12:32 AM
|
|||
|
|||
|
Re: 3 card poker problems....
|
|
#5
04-15-2005, 02:55 AM
|
|||
|
|||
|
Re: 3 card poker problems....
[ QUOTE ]
Don't you have to subtract the straight flushes? 48 possibilities? SGS [/ QUOTE ] Okay. Got you. I was including those as straights.
|
 |
|
|
Linear Mode
