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Old 01-01-2005, 06:57 PM
Timer Timer is offline
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Join Date: Dec 2002
Posts: 128
Default Ed Miller 27/7 ????

If the board reads k-9-5-3 aren't there 10 ways you can have a set with a k-j already out?

I think I can understand how he comes up with the 27 ways you can make two pair. In order to do this he is eliminating the possibility that the opponent has 95 or 93.

But the set calculation I don't understand. I'm obviously overlooking something simple.

Thanks
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  #2  
Old 01-01-2005, 10:27 PM
pudley4 pudley4 is offline
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Join Date: Oct 2002
Location: Mpls, MN
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Default Re: Ed Miller 27/7 ????

[ QUOTE ]
If the board reads k-9-5-3 aren't there 10 ways you can have a set with a k-j already out?

I think I can understand how he comes up with the 27 ways you can make two pair. In order to do this he is eliminating the possibility that the opponent has 95 or 93.

But the set calculation I don't understand. I'm obviously overlooking something simple.

Thanks

[/ QUOTE ]

In the book, the player who checkraises you on the turn is the same player who bet into you on the flop. The 3 came on the turn. So unless this guy is retarded (we can still use that word here, right?), he doesn't have 33. So that leaves 1 KK, 3 99, and 3 55 for him to have.
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