M&M question........

[SGS]

Here is a problem on my freinds final and he asked me for help but I apparently forgot exactly how to do it. This is pretty simple and straight forward.

Assume the following information:

A tub contains 500 plain m&m’s. 13% of them are brown, 14% are yellow, 13% are red, 24% are blue, 20% are orange and 16% are green. Suppose that two m&m’s are selected at random from the tub. Assume that the first m&m is replaced before the second is drawn.

Calculate the probability that at least one of the m&m’s is blue. Thanks in advance.

SGS

[gaming_mouse]

76% are non-blue. Just do:

1 - (.76)^2