Two Plus Two Older Archives  

Go Back   Two Plus Two Older Archives > PL/NL Texas Hold'em > Small Stakes Pot-, No-Limit Hold'em
FAQ Community Calendar Today's Posts Search

Reply
 
Thread Tools Display Modes
  #1  
Old 11-10-2004, 11:27 PM
pittisit pittisit is offline
Junior Member
 
Join Date: Oct 2004
Posts: 12
Default Please help with my calculations here !!!!!!

I have been getting beaten up with sets to my overpairs recently and was just wondering about my calculations here..... here is one example of a hand

Sorry no converter....100NL i have QQ make it $10 to go,
3 early limpers call...POT ~$45
flop 679
checked to me i bet $30,
guy reraises me for all his chips which makes it $60 more to me..pot now around $160..

obvious set rigth...anyway my question is what % of the time does this guy not have to have a set for my call to be correct instead of folding and losing $45 100% of the time...could someone please show me the correct way to figure this out..i did it in my own little way an come up with a number somewhere around 20% of the time he has to have a hand like A9 for my call to be better than a fold..Obviously if i knew he had a set a fold is best..but in these games you just never know.
Reply With Quote
  #2  
Old 11-11-2004, 04:34 AM
phisfliuch phisfliuch is offline
Junior Member
 
Join Date: Nov 2004
Posts: 12
Default Re: Please help with my calculations here !!!!!!

[ QUOTE ]
what % of the time does this guy not have to have a set for my call to be correct

[/ QUOTE ]

I was confused by this, but I'll provide a possible jumping off point. Let's say you assume he'll only do this with a set or top pair, ace kicker. There are 3 ways for him to have each of the 3 possible sets. There are 12 ways for him to have top pair, ace kicker. That's a total of 12+9=21 equally likely hands.

EV(call) = (160 * 9/21 * 0.105) + (-60 * 9/21 * 0.895) +
(160 * 12/21 * 0.775) + (-60 * 12/21 * 0.225 )

This is using approximate showdown monte carlo probabilities. Note that the probabilities multiplied by their occurrence add up to 1.0.

I didn't bother solving this but I think given the assumption I made, the call is +EV. To answer YOUR question, you'll have to expand on this according to hands you think he might do this with. As you can see, the "% of time of not having a set" depends on the other hands you select. Set EV = 0 and make sure the probabilities scaled by their occurrence sum to 1.0.

If you are really interested in this, you might take a stab at it, then post under Probabilites to get a check of your math and your assumptions.

Reply With Quote
  #3  
Old 11-11-2004, 07:50 AM
pittisit pittisit is offline
Junior Member
 
Join Date: Oct 2004
Posts: 12
Default Re: Please help with my calculations here !!!!!!

i was not aware of the other forum....I appreciate it.
Reply With Quote
Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 08:06 AM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2024, vBulletin Solutions Inc.