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  #1  
Old 01-25-2002, 02:34 PM
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Default Question regarding cute problem



I'm not sure I understand the problem statement.


"Three players: Mr A has one dollar. Mr B has two dollars. Mr C has three dollars. Every hand they each ante a buck and run the cards. That continues until only one player is left."


What happens when a participant is left w/ $0.50, are they out because they can't ante, or are they in for 3/5 of the pot? Will it matter?
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  #2  
Old 01-25-2002, 02:40 PM
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Default a 33-cent rake - 1/9 of pot - is implied *NM*




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  #3  
Old 01-25-2002, 02:45 PM
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Default 2Cryptic4Me - N/M *NM*




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  #4  
Old 01-25-2002, 04:20 PM
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Default My question first raised below



I see my question was first raised below by "Chr", under DS's original post with the subject line "You sure you have the right solution David?" I hadn't examined the whole thread before posting, and Chr's complaint was loss to me in the mass of stuff in that thread -- but credit where it is due...
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  #5  
Old 01-25-2002, 07:40 PM
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Default Re: My question first raised below



He took his lead from me.


"what if there's a tie" under the solution thread.
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  #6  
Old 01-25-2002, 07:45 PM
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Default Re: My question first raised below



Right Sammy. It was you who saw this, but nobody gave an answer even though i commented it in the subjectline. So i tried to post it under DS solution, but still the answer is missing...
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  #7  
Old 01-25-2002, 07:46 PM
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Default corrected again



Well I still haven't seen your post, but I'll take your word for it without hesitation. At the same time, I wouldn't be the least surprised if he found this lack of robustness in the offered solution independently...
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  #8  
Old 01-25-2002, 07:49 PM
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Default Again!



I guess he didn't make the complaint independently. I did... I think...
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  #9  
Old 01-25-2002, 08:21 PM
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Default Re: corrected again



This is a math problem. I would have thought it obvious that I assumed there could be no ties.
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  #10  
Old 01-25-2002, 09:20 PM
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Default Re: corrected again



Cute. Where I studied maths, your solution would be called 'wrong' -- in math, there is no elegance without rigor.
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