full house in seven stud probability

[degenerategambler]

if i hold three pairs with none of my needed cards having been shown on the board up to this point what are the odds of completing to a full house?what about with trips and three other random cards assuming none of the other cards have shown up on the board either. I would appreciate any help. Thanks

[aloiz]

Since you didn't specify the number of other players in the hand, you can do the following. Let x = number of cards you can see or have seen (all as you specified are not your outs).
The odds that you make a boat if you have 3 pairs = 6/(52 - 6 - x).
The odds that you make a boat or better if you have trips = 10/(52 - 6 - x).

aloiz

[degenerategambler]

thanks alot, i appreciate it