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#1
07-14-2004, 11:40 PM
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What are the odds of this?
Hello. I was playin in a tournament today when I got A,K suited. I called down a player to see that he also had A,K suited. I was wondering, what are the odds that 2 people on the same hand have A,K suited.
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#3
07-15-2004, 08:20 AM
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Re: What are the odds of this?
It was a full 10 people table
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#4
07-15-2004, 09:46 AM
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Post deleted by Mat Sklansky
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#5
07-15-2004, 10:17 AM
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Re: What are the odds of this?
[ QUOTE ]
If you are dealt KA, the probability for at least one opponent to be dealt KA is: 9*n/C(50,2)- (n*(n-1)/2)*P(two opponents hold KA)+ (n*(n-1)*(n-2)/6)*P(three opponents hold KA), where n is the number of your opponents. The probability for two specific players to be dealt KA is (16/C(52,2))*(9/C(50,2)). Do the calculations...  [/ QUOTE ] Correct, but the original question asked for the odds of at least 2 players being dealt AK suited, not the probability of at least one opponent being dealt AK when you are dealt AK.
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