Suited Connectors...

[DoctorWard]

thanks for the post...

I would agree with the basic methodology however, I would disagree with the odds for "2-3 suited and Q-K suited". Here I would propose the following:

For 2-3 suited and K-Q suited:
126 combinations give you a straight and only a straight (not 124 as previous)
163 combinations give you a flush and only a flush.
2 combinations give you a straight flush.

Assuming that I am correct with the above statement then the odds would be

A-2: 1/13 x 228/19600 = 228/254800
2-3: 1/13 x 291/19600 = 291/254800
3-4: 1/13 x 354/19600 = 354/254800
4-5: 1/13 x 417/19600 = 417/254800
5-6: 1/13 x 417/19600 = 417/254800
6-7: 1/13 x 417/19600 = 417/254800
7-8: 1/13 x 417/19600 = 417/254800
8-9: 1/13 x 417/19600 = 417/254800
9-T: 1/13 x 417/19600 = 417/254800
T-J: 1/13 x 417/19600 = 417/254800
J-Q: 1/13 x 354/19600 = 354/254800
Q-K: 1/13 x 291/19600 = 291/254800
K-A: 1/13 x 228/19600 = 228/254800

Summing to 4665/254800, or 1.8308%, or 1 in 54.62 times.

Agreed?