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What is the mean high card that you will be dealt in a hold'em hand?
How do you calculate this?
(sorry if this is a really dumb q)
-MG
There are:
4 chose 2 '2 high' hands
8 chose 2-4 chose 2 '3 high' hands
12 chose 2-8 chose 2 '4 high' hands
16 chose 2-12 chose 2 '5 high' hands
...
52 chose 2 - 48 chose 2 'A high' hands
You'll have to figure out what the average of K and 2 is yourself.
Ahh.. k.. I get it...
Thing is, I was really hoping this would be easier because what I really want to know is:
With 10,9,8,..,2 players left at the table, what is the average high hand at the table?
Basically, if I am first to act, should I push in with my hand? Is it higher than X number of random hands.
-MG
N-player jam or fold type stuff is computationally difficult. There's a bunch of published stuff on pre-flop play out there that's pretty good for normal situations.
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