Mr. Curious
09-30-2005, 04:02 PM
Three all-ins on a board of AQT:
Hand 1: AQ
Hand 2: AT
Hand 3: QT
For the flop to come up AQT, the probability is 2/46 * 2/45 * 2/44 = .000087834
How do I adjust the odds of the hands to figure out the total likelyhood of the board + the hands?
Is it ((4/52 * 4/51 AQ) * (3/50 * 4/49 QT) * (3/48 * 3/47 AT)) + (2/46 * 2/45 * 2/44)?
Thanks!
Hand 1: AQ
Hand 2: AT
Hand 3: QT
For the flop to come up AQT, the probability is 2/46 * 2/45 * 2/44 = .000087834
How do I adjust the odds of the hands to figure out the total likelyhood of the board + the hands?
Is it ((4/52 * 4/51 AQ) * (3/50 * 4/49 QT) * (3/48 * 3/47 AT)) + (2/46 * 2/45 * 2/44)?
Thanks!