View Full Version : Poll = Could David Sklansky solve the Beal Theorem??
cwsiggy
03-13-2005, 05:39 PM
So wacha think?
Sponger15SB
03-13-2005, 05:41 PM
What is the difference between the first two choices?
Also, this poll is retarded. He cannot solve the beal theorem
cwsiggy
03-13-2005, 05:42 PM
I thought it was kinda funny. Only on this board do people have no sense of humour.
Sponger15SB
03-13-2005, 05:48 PM
[ QUOTE ]
I thought it was kinda funny. Only on this board do people have no sense of humour.
[/ QUOTE ]
lol, oops!
well i guess it looks like the joke was on me then.
/images/graemlins/frown.gif
cwsiggy
03-13-2005, 06:01 PM
lighten up now - It's Sunday and life is good!!!
Luv2DriveTT
03-13-2005, 06:09 PM
Tha Andy Beal Theorem?
I didn't know the guy was smart enough to have a Theorem named after himself. Unless he had it commissioned...
TT /images/graemlins/club.gif
cwsiggy
03-13-2005, 06:56 PM
haha I'm so stupid! It's called the Beal conjecture!!! oh well.
http://www.bealconjecture.com/
cwsiggy
03-13-2005, 06:59 PM
sorry! the correct answer is Who cares by the way
mostsmooth
03-13-2005, 08:34 PM
is this theorem referring to triangles or just a2+b2=c2 in general?
please forgive me if this is an incredibly stupid question
cardcounter0
03-13-2005, 09:15 PM
No, this would be based on fermat's last theorem of
ax + bx = cx there is no x where x>2
this is a branch conjecture of:
ax + by = cz there are no a,b,c and x,y,z that do not have a common factor.
But is the Beal that came up with this, the same Beal that plays poker???
/images/graemlins/confused.gif
cwsiggy
03-13-2005, 11:33 PM
yes
Daliman
03-13-2005, 11:40 PM
[ QUOTE ]
Tha Andy Beal Theorem?
I didn't know the guy was smart enough to have a Theorem named after himself. Unless he had it commissioned...
TT /images/graemlins/club.gif
[/ QUOTE ]
My first thought too.
cwsiggy
03-13-2005, 11:41 PM
yes guys - I made an error - sorry
and it was too late to correct the first post
My career as a comic is over
Luv2DriveTT
03-14-2005, 01:24 AM
[ QUOTE ]
[ QUOTE ]
Tha Andy Beal Theorem?
I didn't know the guy was smart enough to have a Theorem named after himself. Unless he had it commissioned...
TT /images/graemlins/club.gif
[/ QUOTE ]
My first thought too.
[/ QUOTE ]
oh snap.... I guessed right! I had no idea.
TT /images/graemlins/club.gif
Luv2DriveTT
03-14-2005, 01:25 AM
[ QUOTE ]
yes guys - I made an error - sorry
and it was too late to correct the first post
My career as a comic is over
[/ QUOTE ]
First correct thing you said in this post. OVER. /images/graemlins/tongue.gif
TT /images/graemlins/club.gif
sirio11
03-15-2005, 12:29 AM
[ QUOTE ]
No, this would be based on fermat's last theorem of
ax + bx = cx there is no x where x>2
this is a branch conjecture of:
ax + by = cz there are no a,b,c and x,y,z that do not have a common factor.
But is the Beal that came up with this, the same Beal that plays poker???
/images/graemlins/confused.gif
[/ QUOTE ]
Yes, its him. The guy is really smart, I think there is a prize for anybody who solve the conjecture.
Barry G. said they beat him, just because they take turns with just the best players.
bobbyi
03-15-2005, 04:32 AM
How on earth does one "solve" a theorem?
cwsiggy
03-15-2005, 11:07 AM
Did you read the thread??? It should have said conjecture/problem!!!!!!
vBulletin® v3.8.11, Copyright ©2000-2024, vBulletin Solutions Inc.