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imported_Robert Andersson
01-20-2005, 07:16 PM
hi,

how do you get this figure?
Ive tried to calcultate this but failed.

I would be greatful for any help with the math here.

/Robert

Toonces
01-20-2005, 07:42 PM
50*49*48/(3*2*1)

50 first cards
49 second cards
48 third cards

but since order doesn't matter, divide by the 6 different permutations of the same 3 cards.

imported_Robert Andersson
01-20-2005, 07:48 PM
Ahh! same as C(50,3)!

txs a lot

sillyarms
01-20-2005, 08:20 PM
So if order did matter it would be 50*49*48 ?

silly

gaming_mouse
01-20-2005, 09:38 PM
[ QUOTE ]
So if order did matter it would be 50*49*48 ?

silly

[/ QUOTE ]

Yes