#1
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check my math.
the odds of getting AK before the flop.
8/52*4/51 |
#2
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Check
"Check my math. The odds of getting AK before the flop :
8/52*4/51" Your way gives (8/52)*(4/51)= 0.0120663650075414781297134238310709 Another way : There are C(8,2)=28 combinations made between As and Ks. Taking out the AA and KK combinations, which are 2*C(4,2)= 2*6=12 combinations of AA and KK overall, we get 28-12=16 combinations of AK. Measured against the total combinations of 2-card hands, C(52,2)=1326, this gives the probability of being dealt AK, ie 16/1326= 0.0120663650075414781297134238310709 So both ways give the same result, 1.2% or abt 82:1 against. [Your (8/52)*(4/51) is (8*4)/(52*51)=32/2652, which simplifies to 16/1326.] |
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