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#1
12-11-2002, 08:40 AM
 Webster Senior Member Join Date: Nov 2002 Posts: 835
Shorthanded - two players with same pair - how do you figure

5 man table - Split pot with both winners having 88.

IS it (1/220 * 1/220)= 1/48,000?

Seems I'm missing someting.
#2
12-12-2002, 10:05 AM
 ACPlayer Senior Member Join Date: Dec 2002 Location: Foxwoods, Atlantic City, NY, Boston Posts: 1,089
Re: Shorthanded - two players with same pair - how do you figure

If the question is what is the chances that 2 players in a 5 handed game will be dealt 88 then the answer should be .0015%. Derived as follows:

CHance a player has 88 = .45%
Given that a player has 88 chance that another player get 88 is the hyper geometric distribution selecting 1 success in 4 samples with 2 success samples in a total population of 50 elements multiplied by the chance of getting the last 8. (Then ofcourse multiplied by .45%).

If the question is the chances that it will win the pot and that the pot will be split (well, that is a different kettle of fish).

PS The hypgeomdist function in excel is a great tool to do these things. Try it sometime.

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