#1
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please solve an equation for me
equation:
10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)] n = 29 b = 40 and k=1 and k=2 i need it solved for both k=1 and 2 pls. this is to verify a technical issue and i don't feel like struggling with this when it would take many of you 10 seconds tyvm |
#2
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Re: please solve an equation for me
The answer is "next Thursday"
Seriously, log-base-what? LN? |
#3
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Re: please solve an equation for me
[ QUOTE ]
The answer is "next Thursday" Seriously, log-base-what? LN? [/ QUOTE ] WTF do i know??? does this help doggy? The points formula used to determine the total points awarded to a player in a multi-table tournament (in the top 15% finishers) for any given tournament is: Points = 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)] Where: n is the number of entrants k is the place of finish (k=1 for the first-place finisher, and so on) b is the buy-in amount in dollars (excluding administrative fee). For freerolls the buy-in is $0 Example 1: A player takes third place in a $20 tournament with a field of 150 players. Here: n = 150, k=3, b=20 The total points awarded to this player are: = 10 * [sqrt(n)/sqrt(k)] * [1+log(b+0.25)] = 10 * [sqrt(150)/sqrt(3)] * [1+log(20+0.25)] = 10 * sqrt(50) * (1+1.31) = 10 * 7.071 * 2.31 = 163.09 (rounded up) |
#4
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Re: please solve an equation for me
k=1 --> 140.271
k=2 --> 99.187 |
#5
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Re: please solve an equation for me
technically you posted an expression, not an equation - but since you were right it would take like 10 seconds... use our friend google to evaluate the expression:
google evaluates the expression for us to get result for k = 1: 10 * ((29^.5) / 1) * (1 + log(40.25)) = 140.270936 k =2 gives you this: 10 * ((29^.5) / (2^.5)) * (1 + log(40.25)) = 99.1865299 HTH, ninjageek |
#6
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Re: please solve an equation for me
That's what I got.
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#7
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Re: please solve an equation for me
tyvm
there was a glitch and this dude's name was stuck at top (he went out first 10 minutes) and my tourney report never came. for the wsop contest i need to know 1. whether it was worth bringing to the attention of support (which it is cuz the points double) and 2. i want to check tomorrow and see what was actually awarded before i bother them edit: and as you can see on left, it says i finished 2nd |
#8
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Re: please solve an equation for me
[ QUOTE ]
The answer is "next Thursday" Seriously, log-base-what? LN? [/ QUOTE ] If it was the "natural log" it would have been Ln in the equation, "LOG" nomenclature is Log base 10 |
#9
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Re: please solve an equation for me
[ QUOTE ]
If it was the "natural log" it would have been Ln in the equation, "LOG" nomenclature is Log base 10 [/ QUOTE ] see, it is shiit like this that makes my |
#10
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Re: please solve an equation for me
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