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  #1  
Old 08-13-2005, 06:41 PM
Schizo Schizo is offline
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Default SImple probability question

Folded to unknown CO, checks. Button folds. Hero raise with ATo in the SB. Only CO calls.

Flop is KT6r.



How many ways can villian have JQ? 16?

How many ways can villian have a K?

How many ways can villian have a T or 6?
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  #2  
Old 08-13-2005, 07:13 PM
Luzion Luzion is offline
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Default Re: SImple probability question

[ QUOTE ]
Folded to unknown CO, checks. Button folds. Hero raise with ATo in the SB. Only CO calls.

Flop is KT6r.



How many ways can villian have JQ? 16?

[/ QUOTE ]
There are 16distinctive ways to hold QJ in different combinations of suits, yes...

C(52,2) = 1326 ways to be dealt 2 cards...
16/1326 = 1.2% chance to be dealt QJ

[ QUOTE ]
How many ways can villian have a K?

[/ QUOTE ]
You mean a King and another non-King card right? 192 different ways...
192/1326 = 14.48% to be dealt exactly just one King.

If you mean at LEAST one King... 198 different ways
198/1326 = 14.93%

[ QUOTE ]
How many ways can villian have a T or 6?

[/ QUOTE ]

Exactly just one Ten, no Six...
176 ways
176/1326 = 13.27%

Exactly one Six, no Ten
176 ways
176/1326 = 13.27%

Exactly one six AND ten
16 ways
16/1326 = 1.21%

66 or TT
6 ways each, 12 total
12/1326 = 0.9%
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  #3  
Old 08-14-2005, 03:42 AM
OrianasDaad OrianasDaad is offline
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Default Re: SImple probability question

NM, I forgot to count suited hands.
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  #4  
Old 08-14-2005, 03:53 AM
Luzion Luzion is offline
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Default Re: SImple probability question

Your math is a bit wrong. Lets say you want to find the probability of KQo....

(8/52) * (3/51) = 0.00905 - 0.91%

1st card can be either a King or a Queen for 8 cards.. 2nd card must not be a repeat, and cannot be of the same suit...
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  #5  
Old 08-15-2005, 12:54 AM
KJL KJL is offline
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Default Re: SImple probability question

[ QUOTE ]
C(52,2)= 1326

[/ QUOTE ]
Isn't that supposed to be C(47,2) because we know 5 cards. And when you count the chance of having a ten, you have to remember, that the hero has AT. So everything is a little off. It is easy to make these subststions tho so it is not a big deal.
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  #6  
Old 08-15-2005, 02:13 AM
Luzion Luzion is offline
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Default Re: SImple probability question

[ QUOTE ]
[ QUOTE ]
C(52,2)= 1326

[/ QUOTE ]
Isn't that supposed to be C(47,2) because we know 5 cards. And when you count the chance of having a ten, you have to remember, that the hero has AT. So everything is a little off. It is easy to make these subststions tho so it is not a big deal.

[/ QUOTE ]

Oh yeah... thats a good point. I was assuming the probability that you would be dealt specific cards. [img]/images/graemlins/frown.gif[/img]
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