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  #21  
Old 08-08-2002, 09:21 PM
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Default Re: Two Questions



Just a) for now.


Let P(n)= the probability of throwing a pair of dice n times w/o throwing a seven.


P(n)={5/6}^n


Now P(3)> 1/2 while P(4)
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  #22  
Old 08-09-2002, 05:33 AM
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Default question A is misleading.



question a is misleading. it can be interpreted as: 'how many times must you throw 2 dice that the next throw is more likely than not to be a 7?' or as 'how many times must you throw 2 dice so that you will be more likely than not to have thrown a 7 in that sequence?'
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  #23  
Old 08-14-2002, 01:42 AM
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Default Re: question A is misleading.



1. Never 2. 20,000 If the chances are 1 out of 40,000 then half the time i will hit it before 20,000 and half the time I will hit it after 20,000.
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