#11
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Re: Math question (maybe our resident rocket scientist can help)
Let's not forget this little gem:
a = x a+a = a+x 2a = a+x 2a-2x = a+x-2x 2(a-x) = a+x-2x 2(a-x) = a-x 2 = 1 |
#12
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Re: Math question (maybe our resident rocket scientist can help)
i believe your logic is flawed.
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#13
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Re: Math question (maybe our resident rocket scientist can help)
what we're actually saying is that 1 - [1 - {1/(10*n)}] tends to 0 as n tends to infinity.
1 - 0.9 1 - 0.99 1 - 0.999 ... 1- 0.9999999999999 etc. so since A minus the limit of B equals 0, the limit of B = A. but limit of B = 0.99999999999999...... |
#14
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Re: Math question (maybe our resident rocket scientist can help)
[ QUOTE ]
i believe your logic is flawed. [/ QUOTE ] There's nothing wrong with it at all.. ITs the way you convert a repeating decimal to fraction.. eg.. n = .27272727...... 100n =27.2727272727 100n -n = 27 99n = 27 n=27/99 27/99 = .2727272727272727 Or, how about an infinite geometric sum.. .999999999999= .9+.09+.009 +.0009 etc.. = sum .9*.1^n let n -> infinity= sum a*r^n where a = .9, r = .1.. = a/(1-r) = .9/(1-.1) = .9/.9 = 1 |
#15
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Re: Math question (maybe our resident rocket scientist can help)
This thread blows. Next.
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#16
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Re: Math question (maybe our resident rocket scientist can help)
[ QUOTE ]
Let's not forget this little gem: a = x a+a = a+x 2a = a+x 2a-2x = a+x-2x 2(a-x) = a+x-2x 2(a-x) = a-x 2 = 1 [/ QUOTE ] Can't divide by zero (a-x = 0) Sheesh, they don't make rocket scientists like they used to... [img]/images/graemlins/wink.gif[/img] |
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