Poker Probability Problem Post

lilkunta2 · #1 07-20-2005, 05:22 AM

was doing some thinking. need some verification (if right) and correction (if wrong)

there are 8 ways to make a pocket pair, and 16 ways to make any 2 unsuited cards. I take a sample of top hands let's say....

AA
KK
QQ
JJ
AK (suited or unsuited)
AQ (suited or unsuited)

now,,, you have 3 pocket pairs for 4x8=32 combinations and you have 2 off rank hands 16x2= 32

so the total is 64

there are 1326 combinations for hands,,,,

64/1326=.0482 lets round up to .05 for arguments sake.

this means that the chances of getting dealt on of these hands is (about) 5%

and this also means that the chance of any person at a 10 person table having one of these hands is (.05x10) or %50

this means that once in every 2 rounds at a full table, you will get dealt one of these hands.

is this correct? becuase it seems like hands like that don't come around that often. please correct me if i am wrong.

thanks

Josh W · #2 07-20-2005, 05:26 AM

there are 6 ways to have a pocket pair, 12 ways to have unsuited cards (not counting pairs) and 4 ways to have suited cards.

#3 07-20-2005, 02:59 PM

correct,
also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500.

Paxosmotic · #4 07-20-2005, 03:02 PM

[ QUOTE ]
correct,
also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500.

[/ QUOTE ]
You're a gimmick, right? Aces are 1 in 221. You have a 1 in 17 chance of being dealt a pair, and 1 in 13 of those are aces.

bobman0330 · #5 07-20-2005, 03:17 PM

Furthermore, the odds of no one having a PP =
(1- 1/17)^10 = 54%

krimson · #6 07-20-2005, 05:11 PM

[ QUOTE ]
[ QUOTE ]
correct,
also, another general rule of thumb I have heard is that at a 10 handed table, at least 1 person will have a pp. I have read ur odds of getting aces are 1/6500.

[/ QUOTE ]
You're a gimmick, right? Aces are 1 in 221. You have a 1 in 17 chance of being dealt a pair, and 1 in 13 of those are aces.

[/ QUOTE ]

I wouldn't questions his knowledge. He's read every poker book there is!