|
|
|
|
#1
12-20-2005, 02:18 PM
|
|||
|
|||
Re: my math must be flawed, cuz this doesnt sound right
Because of the "(only one person gets them)" clause. If more than one person gets them, it's counted twice.
|
|
#2
12-20-2005, 04:01 PM
|
|||
|
|||
|
Re: my math must be flawed, cuz this doesnt sound right
So you are saying that with all the different permutations of the 1326 hands dealt to 10 people, whenever AA comes up twice within the 10 hands you count it TWICE towards the % of AA coming up?
That does not make mathematical sense. Once the condition (AA) is met you do not look for more satisfied conditions within the range (that set of 10 hands). You are inflating the results.
|
|
#3
12-20-2005, 04:27 PM
|
|||
|
|||
|
Re: my math must be flawed, cuz this doesnt sound right
[ QUOTE ]
That does not make mathematical sense [/ QUOTE ] I agree, that's why I fixed your calculation. [ QUOTE ] You are inflating the results [/ QUOTE ] No, I'm deflating them, from your inflated figure. Edit: And actually, this doesn't even factor in the fact that you want only hands where one player has them, it just removes the double counting of the times when two people have A-A.
|
 |
|
|
Hybrid Mode
