Two Identical flops

[fuego527]

while your answer is correct, its pretty deluded

the (more easliy understandable) answer is : (1/50)(1/51)(1/52) = 1/132600 = .0008%

this is the odds that 2 predetermined flops will be identical

the odds that after seeing a flop that one of your other 3 tables will contain the same flop is .0008%*3 or .0024%