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#1
11-17-2005, 11:43 AM
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Drinking games lead to question my probability, meh
4 random people sitting at a table, Px= Probability of the amount of left handed people at the table.
p0 = .6568 p1 = .2916 p2 = .0486 p3 = .0036 p4 = .0001 The probability that at any random table in the UK where 4 people are sat are all left handed = 1000th? (assuming that the probability of a person being left handed is .1) 
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#2
11-17-2005, 01:07 PM
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Re: Drinking games lead to question my probability, meh
Drunk posts always make more sense when you read them in reverse:
Assume P(lefty) = 10%. Is P(all 4 people lefty) = one 1000th? [ QUOTE ] 4 random people sitting at a table, Px= Probability of the amount of left handed people at the table. p0 = .6568 p1 = .2916 p2 = .0486 p3 = .0036 p4 = .0001 [/ QUOTE ] Yes. Excellent.
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