#1
|
|||
|
|||
Holding a pocket pair what is the probability of flopping a full house
Holding a pocket pair what is the probability of flopping an exclusive full house (without trips on the board)?
[ QUOTE ] C(2,1)<-Set * C(48,1) * C(3,1)<-Filling Pair ---------------------------------------------- C(50,3)<-Total # of possible flops . 288 ------ ~ .147% 19600 [/ QUOTE ] Can anyone verify if this is correct? |
#2
|
|||
|
|||
Re: Holding a pocket pair what is the probability of flopping a full house
Not an expert on math,
But I think you are missing if trips hit the board (4-4-4, 9-9-9). so there's 12 more possible flops. |
#3
|
|||
|
|||
Re: Holding a pocket pair what is the probability of flopping a full house
Thank you for the responce but I was intentionally trying to avoid that situation of trips on board. As a note yesterday I was able to limp in with A 4 suited. Three players were in the flop. Trip 10's fell on the flop. The pot odds were not good so I folded. 4 fell on the turn followed by a river A. One of the other players raised hoping his 10's full of A's would hold up until the quad 10's was shown.
|
#4
|
|||
|
|||
Re: Holding a pocket pair what is the probability of flopping a full house
I think you're double counting.
[C(2,1) * C(12,1) * C(4,2)]/C(50,3) = 144/19600 or .734% The way you did the math, you still have the decimal in the wrong place and it would be 1.47% not .147%. |
|
|